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author | Jeremy Evans <code@jeremyevans.net> | 2021-04-09 10:44:07 -0700 |
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committer | Jeremy Evans <code@jeremyevans.net> | 2021-04-09 10:44:07 -0700 |
commit | 9c31fb61148c28153ca084149b7e887abdfa408a (patch) | |
tree | 67a5397f5bb280fcab6c9b88868cb764f8855792 | |
parent | 582f4bc1889c3161f47a76b46b60d5b9c6fb0bde (diff) |
Fix documentation for Enumerator::Lazy#with_index
If a block is given, it returns a lazy enumerator that will iterate
over the block, it doesn't iterate over the block immediately.
Fixes [Bug #17789]
-rw-r--r-- | enumerator.c | 3 |
1 files changed, 2 insertions, 1 deletions
diff --git a/enumerator.c b/enumerator.c index a43434dd94..3ea4330802 100644 --- a/enumerator.c +++ b/enumerator.c @@ -2709,7 +2709,8 @@ static const lazyenum_funcs lazy_with_index_funcs = { * lazy.with_index(offset = 0) {|(*args), idx| block } * lazy.with_index(offset = 0) * - * If a block is given, iterates the given block for each element + * If a block is given, returns a lazy enumerator that will + * iterate over the given block for each element * with an index, which starts from +offset+, and returns a * lazy enumerator that yields the same values (without the index). * |